SOLUTION: I'm working on a probabilities question concerning the central limit theorem. The course is showing me the steps: Let mu x_bar represent the mean of the distribution. mux_ba

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Question 889243: I'm working on a probabilities question concerning the central limit theorem. The course is showing me the steps:
Let mu x_bar represent the mean of the distribution.
mux_bar = mu = 9.6
Correct! Good job!
Step 2:
Let sigmax_bar represent the standard deviation of the x_bar distribution.
sigmax_bar = sigma/

n space = 1.2/

5 space = 0.54
I get to step 2 which should say sigma x(bar) times the square root of the sample number or 1.2 time the square root of 5. every time I enter this into my calculator i get 2.68 but they say the answer is 0.54. What am I doing wrong?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
I'm working on a probabilities question concerning the central limit theorem. The course is showing me the steps:
Let mu x_bar represent the mean of the distribution.
mu x-bar = mu = 9.6
Correct! Good job!
==================================
Step 2:
Let sigma x=bar represent the standard deviation of the x-bar distribution.
sigma x-bar = sigma/sqrt(n) = 1.2
I get to step 2 which should say sigma x(bar) times the square root of the sample number or 1.2 time the square root of 5. every time I enter this into my calculator i get 2.68 but they say the answer is 0.54. What am I doing wrong?
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Comment:: You did not post the original Step 2 problem.
I guess you are asked to find sigma if n = 5.
If so, sigma = 1.2*sqrt(5) = 2.68
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Cheers,
Stan H.
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