SOLUTION: Thre are twelve raffle tickets, three of which are winners. Find the probability that in a sample of 5 tickets there will be no more than one winning ticket.

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Question 878804: Thre are twelve raffle tickets, three of which are winners. Find the probability that in a sample of 5 tickets there will be no more than one winning ticket.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
p(winner) = 3/12= .25, n = 5
P(x ≤ 1) = binomcdf(5, .25, 1) = .6328
0r Using P+%28x%29=+highlight_green%28nCx%29%28p%5Ex%29%28q%29%5E%28n-x%29+
P(x ≤ 1) = P(0) + P(1) = (.75)^5 + 5C1(.25)^1(.75)^4
nCx+=+%28n%21%29%2Fx%21%28n+-+x%29%21%29