SOLUTION: To qualify for security officers’ training, recruits are tested for stress tolerance. The recruits in the top 38.7% qualify for advanced training. The scores are found to be normal

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Question 868730: To qualify for security officers’ training, recruits are tested for stress tolerance. The recruits in the top 38.7% qualify for advanced training. The scores are found to be normally distributed with a mean of 88 and standard deviation of 6.2 (these are not percent scores). Determine the lowest whole number score for an applicant who qualifies for advanced training.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
z = invNorm(.613) = .2871
.2871*6.2 + 88 = X (rounded UP, the lowest score)