Question 867492: Suppose we want to estimate, by random sampling, the proportion of all college students who think they are getting a good education in college. Find, with 95 percent confidence, the number of such students that should be randomly sampled if we want the margin of sampling error to be no more than three percentage points.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Find, with 95 percent confidence, the number of such students that should be randomly sampled if we want the margin of sampling error to be no more than three percentage points.
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Since E = z*s/sqrt(n),
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n = [z*s/E]^2
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Your Problem:
n = [[1.96*s/0.03]^2
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Note:: The standard deviation is missing from your post
so "n" cannot be calculated.
Cheers,
Stan H.
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