Question 859202: A random variable follows a binomial distribution with a probability of success equal to 0.45. For n=11, find the probability of 1 success, probability of fewer than 4 successes, probability of at least 8 successes.
Answer by ewatrrr(24785) (Show Source):
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Hi,
p = .45, n = 11
P(x = 1) = binompdf(11, .45, 1)= .0125
P(x ≤ 4) = binomcdf(11, .45, 4)= .3971
P(x ≥ 8) = 1 – P(x ≤ 7) = 1 - binomcdf(11, .45, 7)= .061
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