SOLUTION: In a certain county, 59% of houses have a pool. 86% have a pool or 2-car garage, 19% have both. If a house in this county is selected at random, what is the probability that the ho

Algebra ->  Probability-and-statistics -> SOLUTION: In a certain county, 59% of houses have a pool. 86% have a pool or 2-car garage, 19% have both. If a house in this county is selected at random, what is the probability that the ho      Log On

 

Hi,

Let x represent percentage with 2-car garage

P(A or B) = P(A) + P(B) - P(A and B)

 86% = 59% + x - 19%

 46% = x,  percentage with 2-car garage