SOLUTION: Please can you help me!
Question: One in four adults says he or she has no trouble sleeping at night. You randomly select five adults and ask if he or she has no trouble sleeping
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Probability-and-statistics
-> SOLUTION: Please can you help me!
Question: One in four adults says he or she has no trouble sleeping at night. You randomly select five adults and ask if he or she has no trouble sleeping
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Question 856392: Please can you help me!
Question: One in four adults says he or she has no trouble sleeping at night. You randomly select five adults and ask if he or she has no trouble sleeping at night.
1. Construct a binomial distribution.
2. Graph the binomial distribution using a histogram.
3. Describe the shape of the histogram.
Construct a binomial distribution. I figured out that n= 5, p= 1/4, q= 3/4. So:
P(0)= 5 C 0 (1/4)^0 (3/4)^5 = 1 (1/4)^0 (3/4)^5 = .2373
P(1)= 5 C 1 (1/4)^1 (3/4)^4 = 5 (1/4)^1 (3/4)^4 = .3955
P(2)= 5 C 2 (1/4)^2 (3/4)^3 = 10 (1/4)^2 (3/4)^3 = .2637
P(3)= 5 C 3 (1/4)^3 (3/4)^2 = 10 (1/4)^3 (3/4)^2 = .0879
P(4)= 5 C 4 (1/4)^4 (3/4)^1 = 5 (1/4)^4 (3/4)^1 = .0146
P(5)= 5 C 5 (1/4)^5 (3/4)^0 =1 (1/4)^5 (3/4)^0 = 9.765625 E-4
I'm confused what I did wrong here because the probability adds up to be over 1, so is this unusual? I am also required to graph a histogram out of this; I just don't think I can because I think my numbers are messed up.
