SOLUTION: The probability of a randomly selected car crashing during the year is .0423. If a family has three cars, find the probability that at least one of them has a crash during the year

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Question 854651: The probability of a randomly selected car crashing during the year is .0423. If a family has three cars, find the probability that at least one of them has a crash during the year? Thank you for the help.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi,
p(crash)= .0423, p(no crash) = .9577
3 cars
P(at least one crash) = 1 - P(no crash) = 1 - (.9577)^3 = 1- .8784 = .1216
Using P+%28x%29=+highlight_green%28nCx%29%28p%5Ex%29%28q%29%5E%28n-x%29+
P(no crash) = (.9577)^3