SOLUTION: The probability of a randomly selected car crashing during the year is .0423. If a family has three cars, find the probability that at least one of them has a crash during the year

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Hi,

 p(crash)= .0423, p(no crash) = .9577

3 cars

P(at least one crash) = 1 - P(no crash) = 1 - (.9577)^3 = 1- .8784 = .1216

Using  

P(no crash) = (.9577)^3