SOLUTION: The average time a person spends at the Barefoot Landing is 103 minutes with a standard deviation of 42 minutes. Find the probability that a randomly selected visitor will spend th

Algebra ->  Probability-and-statistics -> SOLUTION: The average time a person spends at the Barefoot Landing is 103 minutes with a standard deviation of 42 minutes. Find the probability that a randomly selected visitor will spend th      Log On


   

Question 853762: The average time a person spends at the Barefoot Landing is 103 minutes with a standard deviation of 42 minutes. Find the probability that a randomly selected visitor will spend the following times at the seaquarium. Assume the times are normally distributed. Between 100 and 120 minutes. More than 115 minutes.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

mean of 103 minutes with a standard deviation of 42 minutes.

Using TI: The syntax is normalcdf(smaller, larger, µ, σ).

Note: The -9999 is used as the smaller value to be at least 5 standard deviations from the mean.

P(x > 115) =  1 - normalcdf(-9999,115, 103,42)



Using TI: The syntax is normalcdf(smaller, larger, µ, σ).

P(100 ≤ x ≤ 120)= normalcdf(100,120, 103,42)