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Hi,
Find z
A) the middle 77% of a normal distribution is bound by them
23%/2 = 11.5% NORMSINV(0.112)= -1.216, z = ± 1.216
B) the middle 95% of a normal distribution is bound by them
5%/2 = 2.5% NORMSINV(0.025)= -1.96, z = ± 1.96 (graph below)