SOLUTION: Library Patrons in a large metropolitan area were questioned about extending library hours. 72.1% of those polled agreed with extending hours. If four library patrons from this are
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Question 852615: Library Patrons in a large metropolitan area were questioned about extending library hours. 72.1% of those polled agreed with extending hours. If four library patrons from this area were chosen at random, what is that probability that all four would agree to extend hours? Answer by ewatrrr(24785) (Show Source):
Hi,
p(agreeing) = .721
If four library patrons from this area were chosen at random
P(all 4 agreeing) = (.721)^4 where p and q are the probabilities of success and failure respectively. n = 4
4C4 = 1
