SOLUTION: Let X be a binomial random variable with n = 9 and p = 0.2 (nine trials, probability of success = 0.2). Find the probability of 4 successes, i.e., P(X = 4). Give your answer as a

Algebra ->  Probability-and-statistics -> SOLUTION: Let X be a binomial random variable with n = 9 and p = 0.2 (nine trials, probability of success = 0.2). Find the probability of 4 successes, i.e., P(X = 4). Give your answer as a      Log On


   

Question 852556: Let X be a binomial random variable with n = 9 and p = 0.2 (nine trials, probability of success = 0.2). Find the probability of 4 successes, i.e., P(X = 4). Give your answer as a decimal to three decimal places, e.g., 0.123. Round as needed.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Let X be a binomial random variable with n = 9 and p = 0.2 (nine trials, probability of success = 0.2). Find the probability of 4 successes.
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P(x = 4) = 9C4*0.2^4*0.08^5 = binompdf(9,0.05,4) = 0.0006094
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Cheers,
Stan H.
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