SOLUTION: at a local clinic there are 10 men, 8 women. if 3 patients are selected at random find the probability that at least one of the patients is women.

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Question 850156: at a local clinic there are 10 men, 8 women. if 3 patients are selected at random find the probability that at least one of the patients is women.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

P(at least one woman) = 1 - P(no women) = 1 - %2810C3%29%288C0%29%2F%2818C3%29

For ex: Notation used for Combinations:

nCx =  = %28n%21%29%2Fx%21%28n+-+x%29%21%29 

10C3 =  = %2810%21%29%2F%283%217%21%29%29 



%2810C3%29%288C0%29%2F%2818C3%29 = 

More SimplY: Using 'counting'...(1st 10 men, 18people, then 9 men, 17people ...

P(at least one woman) = 1 - P(no women) = 1 - %2810%2F18%29%289%2F17%29%288%2F16%29