SOLUTION: An urn contains 6 red, 6 white, and 2 blue marbles. Three marbles are selected at random and without replacement. What is the probability that one of each color is selected?

Algebra ->  Probability-and-statistics -> SOLUTION: An urn contains 6 red, 6 white, and 2 blue marbles. Three marbles are selected at random and without replacement. What is the probability that one of each color is selected?      Log On


   



Question 848357: An urn contains 6 red, 6 white, and 2 blue marbles. Three marbles are selected at random and without replacement. What is the probability that one of each color is selected?
Answer by swincher4391(1107) About Me  (Show Source):
You can put this solution on YOUR website!
We need to look at the following probabilities.
RWB = (6/14)(6/13)(2/12)
RBW = (6/14)(2/13)(6/12)
.... before we continue
BRW
BWR
WRB
WBR
Notice that we will always get 6*6*2 in the top and 14*13*12 in the bottom.
So we can just rewrite this as 6%2A+%28%286%2A6%2A2%29%2F%2814%2A13%2A12%29%29+=+highlight%2818%2F91%29