Question 847552: Mark Wright can hit the bull's eye with his 22 rifle 30% of the time. He fires 5 shots.
a. calculate his probabilities of making 0, 1, 2, 3, 4, and 5 bull's-eyes
b. Plot the graph of this probability distribution
c. Calculate the probability that he will make at least 2 bull's-eyes.
Answer by ewatrrr(24785)   (Show Source):
You can put this solution on YOUR website!
Hi,
Note: The probability of x successes in n trials is:
P = nCx*  where p and q are the probabilities of success and failure respectively.
In this case p = .30 and q = .70 and n = 5
Using the 'formula' is the 0r
Using TI Calculator
a. binompdf(5,.30, 0) = .1681 0r P = (.30)^0(.70)^5
binompdf(5,.30, 1) = .3602 0r P = 5(.30)^1(.70)^4
binompdf(5,.30, 2) = .3087 0r P = 10(.30)^2(.70)^3
binompdf(5,.30,3) = .1323 0r P = 10(.30)^3(.70)^2
binompdf(5,.30, 4) = .0284 0r P = 5(.30)^4(.70)^1
binompdf(5,.30, 5) = .0024 0r P = (.30)^5(.70)^0
c. P(x≥ 2) = 1 - P(x=0)- P(x=1) = 1 - .1681 - .3602
0r Using TI
1 – binomcdf(n, p, largest x-value) = 1 - binomcdf(5,.30, 1)
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