SOLUTION: I would really appreciate help some help with the following question. If I just knew what formula to use I can usually calculate without any difficulty
For the daily lottery game
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For the daily lottery game
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Question 844088: I would really appreciate help some help with the following question. If I just knew what formula to use I can usually calculate without any difficulty
For the daily lottery game in Illinois, participants select three numbers between 0 and 9. A number cannot be selected more than once, so a winning ticket could be, say, 307 but not 337. Purchasing one ticket allows you to select one set of numbers. The winning numbers are announced on TV each night.
a. How many different outcomes (three-digit numbers) are possible?
b. If you purchase a ticket for the game tonight, what is the likelihood you will win?
c. Suppose you purchase three tickets for tonight's drawing and select a different number for each ticket. What is the probability that you will not win with any of the tickets?
Thank You! Answer by ewatrrr(24785) (Show Source):
Hi,
choosing three numbers between 0 and 9 (10 choices, A number cannot be selected more than once)
that will determine a three-digit number. Note: 0 cannot be used in the hundreds place.
a. How many different outcomes (three-digit numbers) are possible? 9*9*8
b. If you purchase a ticket for the game tonight, what is the likelihood you will win?
c. Suppose you purchase three tickets for tonight's drawing and select a different number for each ticket.
What is the probability that you will not win with any of the tickets?
