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Hi,
Given a binomial distribution where n=50 and p=0.17
mean =
= 8.5
SD = sqrt(50*.17*.83) = 2.66
Note: We can use the normal distribution as a close approximation to the
binomial distribution whenever np ≥ 5 and nq ≥ 5.
Note: np = 8.5 and nq = 41.5
Which of the following is considered an unusual event?
Using a normal distribution as a close approximation to this binomial distribution
a) P(x=8.5) mean
b) P(x=12) close to 1 SD from mean ( 8.5 + 2.66 = 11.16)
c) P(x=15) unusual event (beyond 2 SDs from mean)
d) P(x=6) close to 1 SD from mean (8.5-2.66 = 5.84 )