Question 824318: Using the values, X = 0, 1, 2, 4, 6 and respectively P(X) = .1, .2, ?, .3, .3 find the probability that X is greater than 1.
A) .6
B) .1
C) .7
D) .3
Answer by Edwin McCravy(20054)   (Show Source):
You can put this solution on YOUR website!
X P(X)
---------
0 .1
1 .2
2 ?
4 .3
6 .3
For this to be a probability distribution, the sum
of the probabilities must = 1. So since the probability
of the other four values of X have sum
.1+.2+.3+.3 = .9, then P(2) = 1.0-.9 = .1 and the
distribution is:
X P(X)
---------
0 .1
1 .2
2 .1
4 .3
6 .3
--------
Sum = 1
So P(X > 1) = P(X=2)+P(X=4)+P(X=6) = .1+.3+.3 = .7,
Or what would have been the same,
P(X > 1) = 1 - P(X < 2) = 1-P(X=0)-P(X=1) = 1-.1-.2 = .3
Edwin
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