SOLUTION: hello,
could someone help me please, I have this questions..
1)consider a set of 900 of data values with a mean of 24 and standard deviation of 4.0
a)how many values are lar
Algebra ->
Probability-and-statistics
-> SOLUTION: hello,
could someone help me please, I have this questions..
1)consider a set of 900 of data values with a mean of 24 and standard deviation of 4.0
a)how many values are lar
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Question 824224: hello,
could someone help me please, I have this questions..
1)consider a set of 900 of data values with a mean of 24 and standard deviation of 4.0
a)how many values are larger than 27.00
(report answer to nearest integer)
b) how many values are btween 23.00 and 28.00
(report answer to nearest integer)
You can put this solution on YOUR website! 1)consider a set of 900 of data values with a mean of 24 and standard deviation of 4.0
a)how many values are larger than 27.00
z(27) = (27-24)/4 = 3/4
P(x > 27) = P(z > 3/4) = 0.2266
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Answer: 0.2266*900 = 204
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b) how many values are btween 23.00 and 28.00
z(28) = (28-24) = 4/4 = 1
P(27 < x < 28) = P(3/4 < z < 1) = normalcdf(3/4 , 1) = 0.06
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Ans: 0.06*900 = 54
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Cheers,
Stan H.
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