There are 9 arithmetic means between 11 and 51. The sum of the progression is
11, _, _, _, _, _, _, _, _, _, 51
Notice with 9 terms between them, that
gives a sequence of 11 terms, counting
the 9 and the 51, so n=11, a1=11,
a11 = 51. (There are two elevens,
so don't get them mixed up :).
If we use this sum formula, we don't need d:
Sn =
(a1 + an)
S11 =
(11 + 51)
S11 =
(62)
S11 = 341
Edwin