Hi,
100 players in a football pool each week.
p = 1/100 chances of winning = .01 Losing q = .99
P(winning twice) = = .01 to the nearest one-hundredth
p(not winning twice) 1 - .01 = .99
ODDS of winning twice: 1 in a hundred.
Note: The probability of x successes in n trials is:
P = nCx* where p and q are the probabilities of success and failure respectively.
In this case p= .01 & q = .99
nCx =