SOLUTION: 40% of the students at a particular university are male. 80% of the males and 40% of the
females are studying engineering course. If one student is randomly selected from the
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females are studying engineering course. If one student is randomly selected from the
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Question 809210: 40% of the students at a particular university are male. 80% of the males and 40% of the
females are studying engineering course. If one student is randomly selected from the
students at this university, calculate the probability that the student is
(a) female.
(b) studying engineering course.
(c) male given that they are studying engineering course.
(d) female given that they are not studying engineering course. Answer by edjones(8007) (Show Source):
You can put this solution on YOUR website! .4 are male; .6 are female
.
a).6
.
b)
.4*.8+.6*.4
=.32+.24
=.56
.
c).32/.56 = 4/7
.
d)
1-.56=.44 students not taking engineering.
.6 females not taking engineering*.6 student body=.36
.4*.2=.08 male not taking engineering.
.36+.08=.44
.36/.44=9/11
.
Ed
