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Question 806542:

Found 2 solutions by Edwin McCravy, jishan:
Answer by Edwin McCravy(20054) About Me  (Show Source):
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suppose three coins are lying on a table, two of them with heads facing up and one with tails facing up . one coin is chosen at random and flipped. what is the probability that after the flip the majority of coins ( i.e. at least two of them) will have _?_ facing up
We start with 1H,2H,3T

A.  We choose 1H to flip 1/3 of the time
    1. 1H doesn't change and we end up with 1H,2H,3T 
       1/2 of 1/3 of the time or 1/6th of the time   
    2. 1H changes and we end up with 1T,2H,3T 
       1/2 of 1/3 of the time or 1/6th of the time

B.  We choose 2H to flip 1/3 of the time
    1. 2H doesn't change and we end up with 1H,2H,3T 
       1/2 of 1/3 of the time or 1/6th of the time   
    2. 2H changes and we end up with 1H,2T,3T 
       1/2 of 1/3 of the time or 1/6th of the time

C.  We choose 3T to flip 1/3 of the time
    1. 3T doesn't change and we end up with 1H,2H,3T 
       1/2 of 1/3 of the time or 1/6th of the time   
    2. 3T changes and we end up with 1H,2H,3H 
       1/2 of 1/3 of the time or 1/6th of the time

what is the probability that after the flip the majority of coins ( i.e. at
least two of them) will have HEADS facing up.

That will be P(A1 or B1 or C1 or C2) = 1/6 times 4 = 4/6 or 2/3. 

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what is the probability that after the flip the majority of coins ( i.e. at
least two of them) will have TAILS facing up.

That will be P(A2 or B2) = 1/6 times 2 = 2/6 or 1/3.

Edwin

Answer by jishan(1) About Me  (Show Source):