Question 800971:
A poll of 1000 people reported that 42% expect to win the lottery(yeah right!!!). What is the 99% confidence interval of the true proportion of people who expect not to win the lottery?(Assume that all who participated in the survey responded with either they did expect to win the lottery or not win the lottery.)
Answer by oscargut(2103)   (Show Source):
You can put this solution on YOUR website! Hi,
Answer is: (0.38,0.46)
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Thanks
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