SOLUTION: You have a spinner with numbers 1 through 12, using a simulation what is the probability of getting 3 odd numbers in a row? I did:
1 3 5 7 9 11 which would be exactly half the num
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-> SOLUTION: You have a spinner with numbers 1 through 12, using a simulation what is the probability of getting 3 odd numbers in a row? I did:
1 3 5 7 9 11 which would be exactly half the num
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Question 779031: You have a spinner with numbers 1 through 12, using a simulation what is the probability of getting 3 odd numbers in a row? I did:
1 3 5 7 9 11 which would be exactly half the numbers on the spinner. So 3 spins would be 1/2 x 3 and I ended up with 3/8 which is 37.5%
Did I do this correctly? Answer by 1412(5) (Show Source):
You can put this solution on YOUR website! Permutation(6,3) = 6!/(3! 3!) = 20 ==> Number of ways refer to 3 odds
Permutation(12,3) = 12!/(3! 9!) = 220 ==> Number of the outcomes in the sample space
the final answer = 20/220
= 1/11
