SOLUTION: Question 1:
From past record, 75% of the retirees stated that they preferred living in an apartment to living in a one-family home. A random sample of 30 retirees was taken, and t
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From past record, 75% of the retirees stated that they preferred living in an apartment to living in a one-family home. A random sample of 30 retirees was taken, and t
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Question 771919: Question 1:
From past record, 75% of the retirees stated that they preferred living in an apartment to living in a one-family home. A random sample of 30 retirees was taken, and they are asked whether they prefer living in an apartment. 21 of these retirees are responded yes. Construct a 99% confidence interval for the proportion of all retirees who prefer living in an apartment.
Question 2:
A survey is being planned to determine the mean amount of time corporation executives watch TV. A survey indicated that the mean time per week is 12 hours with a standard deviation of 3 hours. It is desired to estimate the mean viewing time within one-quarter hour. The 95% level of confidence is to be used. How many executives should be surveyed?
Question 3:
A population is estimated to have a standard deviation of 10. We want to estimate the population mean within 2, with a 95% level of confidence. How large a sample is required? Answer by oscargut(2103) (Show Source):
You can put this solution on YOUR website! Hi,
I do question 1) here
CI at 99% is:
21/30 +- z(0.005)sqrt((21/30(1-21/30))/30)
= (0.484,0.916)
I can help you with more questions at: mthman@gmail.com
Thanks
