SOLUTION: 1) 40% of all US adults try to pad their auto insurance claims to cover their deductible. Out of 128 claims processed what is the probability that fewer than 45 of the claims hav

Algebra ->  Probability-and-statistics -> SOLUTION: 1) 40% of all US adults try to pad their auto insurance claims to cover their deductible. Out of 128 claims processed what is the probability that fewer than 45 of the claims hav      Log On


   

Question 769997: 1) 40% of all US adults try to pad their auto insurance claims to cover their deductible. Out of 128 claims processed what is the probability that fewer than 45 of the claims have been padded. Round to the nearest thousandths place.

2) Consider the binomial experiment with 20 trials and probability 0.45 on a single trial. Use the normal distribution to find the probability of exactly 10 successes. Round to the thousandths place.
I need to know how to find the endpoints and then I can find the z- score for each and subtract to solve.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
1) 40% of all US adults try to pad their auto insurance claims to cover their deductible. Out of 128 claims processed what is the probability that fewer than 45 of the claims have been padded. Round to the nearest thousandths place.
P(0<= x <=44) = binomcdf(128,0.4,44) = 0.1127
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2) Consider the binomial experiment with 20 trials and probability 0.45 on a single trial. Use the normal distribution to find the probability of exactly 10 successes. Round to the thousandths place.
I need to know how to find the endpoints and then I can find the z- score for each and subtract to solve.
P(x = 10) in binomial becomes P(9.5 < x < 10.5) in a normal approximation.
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Cheers,
Stan H.