Question 769573: Bob,Jane,Harvey,Norman,Alice and Clarissa are running for election.A man and a woman will be elected.List the possible results.
(i)How many different results are possible?
(ii)What is the probability that Harvey and Clarissa are elected together?
(iii)What is the probability that Clarissa is elected?
(iv)What is the probability that Bob is not elected?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Bob,Jane,Harvey,Norman,Alice and Clarissa are running for election.
A man and a woman will be elected.
List the possible results.
(i)How many different results are possible?:::3*3 = 9 man/woman pairs
-----------------------------------------
(ii)What is the probability that Harvey and Clarissa are elected together?::1/9
----------------------------------------
(iii)What is the probability that Clarissa is elected?::: 3/9 = 1/3
-------------------------------------------
(iv)What is the probability that Bob is not elected?::: 6/9 = 2/3
===========================================
Cheers,
Stan H.
=========================
|
|
|
