Question 764516: In a storehouse, 80 goods are kept where 20 of them are damaged. If a good is taken in random, what is the probability of non-damaged good is taken?
How can I solve this? I've tried using probability of c(80,60) but I still can't find the answer.
The choices are:
A. 1/8 B. 3/4 C.1/10 D. 1/20
Thank you
Answer by ramkikk66(644)   (Show Source):
You can put this solution on YOUR website!
Hi,
C(80,60) is the number of ways you can choose a set of 60 from a set of 80. But
that's not what you want here. Here, you are choosing ONE item from 80, because
the problem states that you are choosing one good at random from 80. This
can be done in C(80,1) or 80 ways. Similarly, there are 60 non-damaged goods and
you can choose one from them in C(60,1) = 60 ways.
Probability is defined as Number of favourable outcomes / No. of total possible outcomes.
Here the probability = No. of ways you can choose a non-damaged good / No. of
ways of choosing any one good
= C(60,1)/C(80,1) = 60/80 = 3/4
Hope you got it. Please email me if it's not clear.
:)
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