You can put this solution on YOUR website! Q:
Find the binominal distribution for which the mean is 4 and variance is 3
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A:
If X~Binomial(n, p), then
Mean, E(X) = np and
Variance, Var(X) = npq
np = 4 and npq = 3
Therefore, npq/np = 3/4 = 0.75 OR
q = 0.75
p = 1 - q = 1 - 0.75 = 0.25
0.25n = 4 so n = 16
n = 16 and p = 0.25
X~Binomial(16, 0.25)
P(X = x) =
