Question 754302: A screening program tests people for hookworm infection, and treats them if they are found to be infected. A diagnosis of hookworm infection is made when a hookworm egg is identified by microscopy in a stool specimen, usually involving multiple slides(sample from the stool specimen). The sensitivity of the stool exam is 75% per slide i.e. if a person is infected, there is a 75% chance that the microscopist will identify an egg on a single slide from the stool specimen. How many slides will need to be taken from a given stool specimen to ensure that an infected person will have a probability of at least 99% of receiving treatment?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! A screening program tests people for hookworm infection, and treats them if they are found to be infected. A diagnosis of hookworm infection is made when a hookworm egg is identified by microscopy in a stool specimen, usually involving multiple slides(sample from the stool specimen). The sensitivity of the stool exam is 75% per slide i.e. if a person is infected, there is a 75% chance that the microscopist will identify an egg on a single slide from the stool specimen. How many slides will need to be taken from a given stool specimen to ensure that an infected person will have a probability of at least 99% of receiving treatment?
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n = [z/E]^2*pq
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n = [2.5758/0.01]^2*0.75*0.25 = 12441
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Cheers,
Stan H.
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