SOLUTION: I'm stumped on this one. Can't figure out how to set it up. It doesn't work when setting up a minimum and maximum....or I'm just plain wrong. The annual snowfall in a town has

Algebra ->  Probability-and-statistics -> SOLUTION: I'm stumped on this one. Can't figure out how to set it up. It doesn't work when setting up a minimum and maximum....or I'm just plain wrong. The annual snowfall in a town has       Log On


   



Question 752386: I'm stumped on this one. Can't figure out how to set it up. It doesn't work when setting up a minimum and maximum....or I'm just plain wrong.
The annual snowfall in a town has a mean of 31 inches and a standard deviation of 11 inches. Last year there were 66 inches of snow. How many standard deviations from the means is that?
3.18 above mean
3.18 below mean
.30 above mean
.30 below mean
I'm thinking its 3.18 above

Answer by FrankM(1040) About Me  (Show Source):
You can put this solution on YOUR website!
66-31=35
35/11=3.18 standard deviations above the mean.