SOLUTION: normal distribution with a mean of 61 and standard deviation of 5, how to calculate the standard score equivalents for
x x z t
66
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x x z t
66
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Question 718942: normal distribution with a mean of 61 and standard deviation of 5, how to calculate the standard score equivalents for
x x z t
66 Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! normal distribution with a mean of 61 and standard deviation of 5, how to calculate the standard score equivalents for
x x z t
66
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Not sure what you mean be repeating the x value.
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z(66) = (66-61)/5 = 5/5 = 1
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t(66) = is the same as z(66)
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Cheers,
Stan H.
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