Question 698767: (A) Find the binomial probability P(x = 6), where n = 15 and p = 0.50.
(B) Set up, without solving, the binomial probability P(x is at most 6) using probability notation.
(C) How would you find the normal approximation to the binomial probability P(x = 6) in part A? Please show how you would calculate µ and σ in the formula for the normal approximation to the binomial, and show the final formula you would use without going through all the calculations
somebody please help me
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! (A) Find the binomial probability P(x = 6), where n = 15 and p = 0.50.
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P(x=6) = 15C6*0.5^6*0.5^9 = 15C6/2^15 = 5005/32758 = 0.1527
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(B) Set up, without solving, the binomial probability P(x is at most 6) using probability notation.
P(0<= x <=6) = binomcdf(15,0.5,6)
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(C) How would you find the normal approximation to the binomial probability P(x = 6) in part A? Please show how you would calculate µ and σ in the formula for the normal approximation to the binomial, and show the final formula you would use without going through all the calculations
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u = np = 15*0.5 = 7.5
s = sqrt(npq) = sqrt(7.5*0.5) = 1.936
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P(x = 6) = P(5.5< x <6.5)
z(5.5) = (5.5-7.5)/1.936 = -1.0331
z(6.5) = (6.5-7.5)/1.936 = -0.5165
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P(x = 6) = P(5.5< x < 6.5) = P(-1.0331< z < -0.5165) = 0.1520
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Cheers,
Stan H.
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