SOLUTION: please help me!!!!
if 3 fair coins are tossed, find the probability of each number of heads.
1) 0
2) 2
3) 1 or 2
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-> SOLUTION: please help me!!!!
if 3 fair coins are tossed, find the probability of each number of heads.
1) 0
2) 2
3) 1 or 2
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Question 673571: please help me!!!!
if 3 fair coins are tossed, find the probability of each number of heads.
1) 0
2) 2
3) 1 or 2 Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! It helps if you write down all the possible outcome
H H H
T T T
H H T
H T H
T H H
T T H
T H T
H T T
There are 8 possible outcomes, which is
(1)
no heads. Only T T T fits, so
P( 0H ) = 1/8
---------------
(2)
Exactly 2 heads. There are 3 of these, so
P( 2H ) = 3/8
---------------
(3)
Exactly 1 head or exactly 2 heads. When you see OR, you
add the separate probabilities
P( 1H ) = 3/8
P( 1H ) + P( 2H ) = 3/8 + 3/8
3/8 + 3/8 = 3/4
