SOLUTION: A box contains 7 red balls and 3 black balls. Two balls are drawn. What is the probability of drawing: (a)a red ball, followed by a black ball, assuming that you replace the fir

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Question 667908: A box contains 7 red balls and 3 black balls. Two balls are drawn. What is the probability of drawing:
(a)a red ball, followed by a black ball, assuming that you replace the first ball before drawing the second?
(b)a black ball on each draw, if the first ball drawn is black (assuming there is no replacement)

Found 2 solutions by ewatrrr, act417:
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi,
A box contains 10balls: 7 red balls and 3 black balls.
Two balls are drawn.
with replacement
P(red than black) = %287%2F10%29%283%2F10%29=+21%2F100
without replacement
P(black than black) = %283%2F10%29%282%2F9%29=+6%2F90=+1%2F15

Answer by act417(1) About Me  (Show Source):
You can put this solution on YOUR website!
I have no idea