SOLUTION: A distribution of values is normal with a mean of 231.6 and a standard deviation of 62.4.
Find the probability that a randomly selected value is less than 312.7.
P(X < 312.7)
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-> SOLUTION: A distribution of values is normal with a mean of 231.6 and a standard deviation of 62.4.
Find the probability that a randomly selected value is less than 312.7.
P(X < 312.7)
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Question 667615: A distribution of values is normal with a mean of 231.6 and a standard deviation of 62.4.
Find the probability that a randomly selected value is less than 312.7.
P(X < 312.7) = Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! A distribution of values is normal with a mean of 231.6 and a standard deviation of 62.4.
Find the probability that a randomly selected value is less than 312.7.
P(X < 312.7) =
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z(312.7) = (312.7-231.6)/62.4 = 1.3000
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P(x < 312.7) = P(z < 1.3000) = 0.9031
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Cheers,
Stan H.
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