SOLUTION: find the indicated probabilities using the standard normal table a.) P(0 < z < 1.83) b.) P(-1.18 < z < 0) c.) P(z < 0.95)

Hi, there--

Problem:
Find the indicated probabilities using the standard normal table 
a.) P(0 < z < 1.83) 
Look in your z-table for the value 1.83; find 1.8 along the left side of the table, then follow 
that row to the right until you intersect the 0.03 column. The value is 0.4664. This is the area 
under the normal curve between z=0 and x=1.8---exactly what you are looking for.

b.) P(-1.18 < z < 0) 
Use the fact that the normal curve is symmetric with respect to the y-axis (z=0). So
P(-1.18 < z < 0) = P(0 < z < 1.18). Find the area under the normal curve for this region. Use 
the same process as in problem (a.).

c.) P(z < 0.95)
You need to break this one apart to find the area under the curve.
P(z < 0.95) = P(z < 0) + P(0 < z < 0.95)
The area under the curve for z < 0 is 0.5000 because it is exactly half the region under the 
curve---the total probability must equal 1. To find the region between 0 and 0.95, find 0.9 
on the left side of the table, then follow that row to the 0.05 column. Add the value to 0.5000.

Hope this helps. Send me an email if you want to check your answers.

~Mrs. Figgy
math.in.the.vortex@gmail.com