Question 65372: HI, i need help with this problem:
A new shipment of 9 VCRs, which will be offered at a very low price, are delivered to a store. Unknow to the manager, 4 of the VCRs are defective.
Determine the probability that at least one of the first 3 VCRs sold is defective. Express your answer to the nearest tenth of one percent.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! A new shipment of 9 VCRs, which will be offered at a very low price, are delivered to a store. Unknow to the manager, 4 of the VCRs are defective.
Determine the probability that at least one of the first 3 VCRs sold is defective. Express your answer to the nearest tenth of one percent.
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P(at least one defective) = 1 - P(none defective)
# of ways to choose 3 that are not defective is 5C3
# of ways to choose 3 of any kind out of nine is 9C3
=1 - 5C3/9C3
=1 - (5/9)(4/8)(3/7)
=1- 0.119047...
=0.8809...
Cheers,
Stan H.
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