SOLUTION: one card is ramdomly selected from a shuffled standard deck of 52 card and then a die is rolled. Find the probability of obtaining an ace and a 4

There are 4 aces out of 52 cards.  In probability "out of" means "over",
so

P(ace) = 4 out of 52 = 4 over 52 =  which reduces to .


There is 1 four out of 6 numbers on the die. In probability "out of" means "over", so

P(four) = 1 out of 6 = 1 over 6 = 

We want to know

P(ace AND four).  In probability "AND" means "multiply", so

P(ace AND four) = P(ace)×P(four) = × = 

Edwin