SOLUTION: How many different ways can 4 women and 7 men be selected from 11 married couples (assuming no gay marriages).

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Question 630623: How many different ways can 4 women and 7 men be selected from
11 married couples (assuming no gay marriages).
Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!
"11 women choose 4", that's C(11,4) or 330.

For each of those 330 ways to choose the 4 women, there are

"11 men choose 7", that's C(11,7) or 330 ways to choose the men.

Therefore the answer is C(11,4)·C(11,7) = 330·330 = 108,900 ways.

Edwin