SOLUTION: Overall, the amount of work-hours involved in the festival preparation is normally distributed around 80 hours with a standard deviation of 8 hours.
a) What’s the probability th
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-> SOLUTION: Overall, the amount of work-hours involved in the festival preparation is normally distributed around 80 hours with a standard deviation of 8 hours.
a) What’s the probability th
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Question 624633: Overall, the amount of work-hours involved in the festival preparation is normally distributed around 80 hours with a standard deviation of 8 hours.
a) What’s the probability that the mean number of work-hours will be between 85 and 90?
b) The members at or below the 10%ile of number of worked-hours must attend a one-on-one meeting with their supervisor. At least how many work-hours you should have in order to avoid attending such session?
c) How likely (what is the probability) is it to have the number of involved work-hours below 80?
d) How likely (what is the probability) is it to have the number of involved work-hours below 65?
e) How likely (what is the probability) is it that some employee will have his/her involved work- hours between 73 and 88?
Hi,
I. Recommend understanding how to derive z-score and it's corresponding
Probability (using Excel function NORMSDIST(z)) of data being to the left of x value given
II. Understanding the Standard Normal Curve in terms of z-scores:
Important to Understand z -values as they relate to the Standard Normal curve:
Below: z = 0, z = ± 1, z= ±2 , z= ±3 are plotted.
Note: z = 0 (x equal to the mean) 50% of the area under the curve is to the left and %50 to the right
III. then, unless You have a Calculator You know how to use:
would recommend using a site such as the following to check Your work:
easycalculation.com/statistics/normal-distribution.php