Question 611115: Monte sets his CD player to play the tracks in random order. The CD has 8 tracks: 3 play are string quartets, 4 are vocals, and 1 is a piano. Find the probability that the first three tracks played are a vocal, a string quartet and a piano piece, in that order.
[ C(4,1) + C(3,1) + C(1,1) / C(8,3) = 4+3+1/56 = 8/56 = .143. This (.143) is not the correct answer. Please show the work for this problem].
Thank you in advance, your time is appreciated!
DCM
Answer by jsmallt9(3758)   (Show Source):
You can put this solution on YOUR website! Since order matters, you don't want to be using combinations, C(x,y).
At any one time the probability of of a string quartet would be 3/8. Three string quartets over a total of 8 tracks. Similarly the the probability of a vocal is 4/8 or 1/2 and the probability of a piano is 1/8.
The probability of a vocal, then a string quartet and then a piano piece is the product of those probabilities:
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