SOLUTION: Suppose we want to determine the (binomial) probability (p) of getting 0 (zero) heads in 5 flips of a 2-sided coin. Using the table [(n/x) * p^x * q^(n-x)] what values of n, x, a

Algebra ->  Probability-and-statistics -> SOLUTION: Suppose we want to determine the (binomial) probability (p) of getting 0 (zero) heads in 5 flips of a 2-sided coin. Using the table [(n/x) * p^x * q^(n-x)] what values of n, x, a      Log On


   



Question 610717: Suppose we want to determine the (binomial) probability (p) of getting 0 (zero) heads in 5 flips of a 2-sided coin. Using the table [(n/x) * p^x * q^(n-x)]
what values of n, x, and p would we use to look up this probability, and what would be the probability?

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi,
Note: Use of [(nCx) * p^x * q^(n-x)] below:
P(0 heads in 5 flips)
Note: The probability of x successes in n trials is:
P+=+nCx%2Ap%5Ex%2Aq%5E%28n-x%29 where p and q are the probabilities of success and failure respectively.
In this case p%28heads%29+=+.5 & q(tails) = 1/2 or .5
nCx = n%21%2F%28x%21%28n-x%29%21%29 n+=+5 and x+=+0
P = 5C0(.5)^0(.5)^5 = 1(.5)^0(.5)^5 = +.0313