SOLUTION: 20 voters. 12 favor and 8 oppose. if 5 random voters are selected what is the probability that 3 will favor and 2 will oppose

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Question 610685: 20 voters. 12 favor and 8 oppose. if 5 random voters are selected what is the probability that 3 will favor and 2 will oppose
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi, 

20 voters. 12 favor and 8 oppose. 

5 random voters are selected...

P(3 in favor & 2 Opposed)=  12C3*8C2/20C5 = 220*28/15504

Can recommend Stattrek.com as a cross reference for your statistical calculations.