SOLUTION: An aviary contained 12 birdies and 15 eagles. Bogey left the window open and before Paar shut it, seven of them had flown out. Find the probability that 4 birdies and 3 eagles es

Algebra ->  Probability-and-statistics -> SOLUTION: An aviary contained 12 birdies and 15 eagles. Bogey left the window open and before Paar shut it, seven of them had flown out. Find the probability that 4 birdies and 3 eagles es      Log On


   

Question 609974: An aviary contained 12 birdies and 15 eagles. Bogey left the window open and before Paar shut it, seven of them had flown out. Find the probability that 4 birdies and 3 eagles escaped through the window in alternating order.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi, 

An aviary contained 12 birdies and 15 eagles. 27 BIRDS in all.

seven of them flew out.

P(4 birdies and 3 eagles escaped through the window in alternating order)

P = %2812%2F27%29%2815%2F26%29%2811%2F25%29%2814%2F24%29%2810%2F23%29%2813%2F22%29%289%2F21%29