SOLUTION: an urn contains 5 yellow, 6 green and 7 blue balls. two balls are randomly drawn without replacement. find the probability of the following events:
A. both balls are green
B. t
Algebra ->
Probability-and-statistics
-> SOLUTION: an urn contains 5 yellow, 6 green and 7 blue balls. two balls are randomly drawn without replacement. find the probability of the following events:
A. both balls are green
B. t
Log On
Question 609930: an urn contains 5 yellow, 6 green and 7 blue balls. two balls are randomly drawn without replacement. find the probability of the following events:
A. both balls are green
B. the first ball is blue and the second is yellow
C. there is one green and one yellow ball Answer by ewatrrr(24785) (Show Source):
Hi
urn contains balls: 5 yellow, 6 green and 7 blue balls
two balls are randomly drawn 'without' replacement
A. P(both balls are green) =
B. P(the first ball is blue and the second is yellow) =
C. P(there is one green and one yellow ball)= 6C1*5C1/18C2 = 30/153 = 10/51
