SOLUTION: three persons A,B and C speak at a function along with five other persons. If the persons speak at random, find the probability that A speaks before B and B speaks before C.
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-> SOLUTION: three persons A,B and C speak at a function along with five other persons. If the persons speak at random, find the probability that A speaks before B and B speaks before C.
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Question 609862: three persons A,B and C speak at a function along with five other persons. If the persons speak at random, find the probability that A speaks before B and B speaks before C. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Three persons A,B and C speak at a function along with five other persons. If the persons speak at random, find the probability that A speaks before B and B speaks before C.
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# of ways to succeed:
1st 3 speakers 1 way
Last 5 speakers 5! = 120 ways
Total successful orders of speakers: 1*120 = 120
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# of random orders of speakers: 8! = 40320
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P(ABCxxxxx) = 120/40320
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Cheers,
Stan H.
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