Question 608805: What is the probability of getting exactly 6 heads in 10 coin tosses?
Found 2 solutions by ewatrrr, sunsetatdawn:
Answer by ewatrrr(24785)   (Show Source):
You can put this solution on YOUR website!
Hi
Note: The probability of x successes in n trials is:
P = nCx*  where p and q are the probabilities of success and failure respectively.
In this case p & q are = 1/2 or .5
nCx = 
P(exactly 6 heads in 10 coin tosses) = 210(.5)^6(.5)^4 = .2051
Answer by sunsetatdawn(4)  (Show Source):
You can put this solution on YOUR website! If you are using a probability table to answer this, you have to calculate, n, x, and p. Where n is the number of trials, x is how many you want to get, and p is the probability of success. If looking for failure, you would need q with is 1-p, but as we aren't doing failure, will skip that for now. In this case, n=10 as we toss the coin 10 times. x = 6 as we want 6 heads, p = .5 as we have a .5 chance each trial to get a head. Then, using these you would use the table to find the probability of .205.
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