SOLUTION: <pre>
An 8 sided die, which may or may not be a fair
die, has 4 colors on it; you have been tossing
the die for an hour and have recorded the color
rolled for each toss. Usi
Algebra ->
Probability-and-statistics
-> SOLUTION: <pre>
An 8 sided die, which may or may not be a fair
die, has 4 colors on it; you have been tossing
the die for an hour and have recorded the color
rolled for each toss. Usi
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An 8 sided die, which may or may not be a fair
die, has 4 colors on it; you have been tossing
the die for an hour and have recorded the color
rolled for each toss. Using relative frequency
what is the probability you will roll a brown
on your next toss of the die?
orange brown green yellow
46 23 32 19
An 8 sided die, which may or may not be a fair
die, has 4 colors on it; you have been tossing
the die for an hour and have recorded the color
rolled for each toss. Using relative frequency
what is the probability you will roll a brown
on your next toss of the die?
orange brown green yellow
46 23 32 19
That's a total of 46+23+32+19 or 120 rolls.
You only asked for the probability of brown,
but I'll give all the probabilities:
It came up orange 48 times out of 120, so the
experimental probability of orange is the
fraction which reduces to .
Therefore the probability you will roll an
orange on your next toss of the die is .
It came up brown 23 times out of 120, so the
experimental probability of orange is the
fraction , which doesn't reduce.
Therefore the probability you will roll a brown
on your next toss of the die is
. (That's the answer to your problem).
It came up green 32 times out of 120, so the
experimental probability of orange is the
fraction which reduces to.
Therefore the probability you will
roll a green on your next toss of the die is
.
It came up yellow 19 times out of 120, so the
experimental probability of orange is the
fraction which doesn't reduce.
Therefore the probability you will
roll a yellow on your next toss of the die is
.
Edwin